what? a universal energy formula?!

G-theory©

Formula for everything teaser,

I hear the scientific world is searching for the formula for everything... Well its been staring them in the face like forever... but they've been so busy floundering around in weird metaphysical places, I guess it serves them right that a simple man like me has to do the job for them.

So I will now present a simplified derivation method for the formula for everything as presented and proved in G-theory: Of course before anyone can derive the formula for everything they first need a theory of everything and the formula then upholds the theory. That theory is G-theory.

Energy has been derived as one joule being the energy used while moving an object with a mass of one kilogram sideways for a distance of one meter. One joule is also used and stored by lifting one kilogram over a height of one meter at earth surface over one second. Actually that’s two joules if you think about it but at this stage we’re only talking about the 'lifting in gravity energy' and discounting the 'moving energy'.

Energy is also derived from the gravity accelerated velocity of a one kg object dropped from one meter by (approx) E=2mv so now we have mass being the same, and energy is proportional to velocity measured in meters per second.

The 'second' is a time value we can relate all the relative terms to, and the terminal 'velocity' in meters per second has been caused by gravity. Therefore half the energy from E=2mv is derived from gravity and the other half from mechanical work stored at height.

There are those two pesky energies again but near the surface of the earth they are both the same over the same distance and each determined by E=mv. Now one-energy was stored potential mechanical energy of motion, and the other energy was the stored energy of lifting against gravity in one second. Therefore E (gravity) has full equality with the E (mechanical).

This is not exactly correct, so the gravity component is related to a constant ‘G’ for relationships between the center of the earth and the center of objects elsewhere... which includes our falling object.

The meter part of the height... as well as the meters per second has been derived from gravity-mass relationship in kgs by the orbit of the earth around the sun... from which we derived the 'second'. The mass in kgs is then related to the meter relative to the diameter of the earth. This is converted to volume and related to the weight and volume of one liter of water, which is the standard specific gravity comparison that we need for non molar calculations.

This is then back tied to the kg as mass by m=f/a (m=9.81/981=1kg) where the weight is the concept of gravitational force at rest. All these terms are related but if our equation is to do with atomic matter in moles we need to bring the molar specific gravity into the equation but we can forget that for now.

We also need to know the temperature because that gives proportionality with the energy we are calculating (with some variable proportionality to specific heat even though the heat capacity is open ended up to the limit of universal temperature which we can also calculate). in the following relationships. This also applies to individual atom (nucleon) masses and specific heat.

So for chemical energy we also need specific heat and this applies to all gases and molecules as well as individual atoms but now not nucleons and electrons etc. We can now finish the circular relationship of terms back to the start and we will then have the basis for the equation for everything.

Now the mechanical energy the joule is the same as the electrical energy J through ohms law; where one joule is one watt in one second. This is related to one coulomb of electrons in that second so the energy of one electron is 1eJ (the volt is unity like the second).

Now the eJ is related to one quantum integer step by quantum analysis being the energy used to cause an electron to jump an energy level. This I have proven in the thesis. This will cause one electron to also traverse one coulomb number of atoms in one second. These are all related. This surprising relationship with the second is no accident as we will see.

The speed of light is in meters per second which gives an
immediate relationship with the speed of gravity in meters per second to earth gravity per se and the other terms through

This means the speed of light is now directly proportional
to the speed of gravity (because they are both a flux of velocity and intensity) which caused the velocity of the fall in the first
instant by F_{g}
=ma in related terms.
Now all we need apart from the fine constant is the constant
for gravity losses 'G'.

This term relationship between constants comes about because
the entropic and deferentially acting emr (or light) stress energy tensor is
also distance related by the same inverse square law as the gravitational
stress energy tensor which we then don't have to bring into the argument
because now we can see that if both tensors have the same power law relationship
the form cancels to a relative linear relationship. Now if we know what the
speed of gravity is we can derive an
energy formula for anything we know the mass of... as well as utilizing transposition relationships as required of course... and guess what? It
won't be the specious equation E=mc^{2}
.

All this of course considers that the energy going out as light is somehow being indirectly returned as gravitational energy less entropic losses which we can discount for the moment even though we do know the percentage lost. This is where I disagree with the idea of entropic energy loss causing gravity. That energy is woefully deficient and it simply has to be light energy returning in an energy loop.

So gravitational energy is basically equivalent to light energy over time so universal energy calculations will not be exactly instantaneous but real world and quantum calculations will be for all intents and purposes relating to this exercise.

How do you propose we calculate the speed of gravity? You will need to order a copy of the thesis for that information. Hint: It has something to do with only one of the terms I have just noted and one constant.

No you can't work it out from E=mc^{2} that's not
useful for anything not even for calculating the kinetic energy of a photon... because for one; the form it was derived from
was the equally specious E=mv^{2} and even the true equation 1/2E=mv is a
form only applicable to gravity because the relationship between the energy of
light and the energy of gravity is a relationship between the two stress energy velocities which is not
directly proportional, and only calculable by the equation that's missing. Then
it will work. So E=m?^{ }But that only applies to a photon. What's the formula for everything? You'll need the thesis for that.

neuvophysics.com